What is the equation of a line that is perpendicular to -x+3y=9 and passes through the point (-3,2)

Perpendicular has slope that mutiplies to -1 to the other slope

for
ax+by=c
slope=-a/b

-1x+3y=9
-(-1)/3=1/3

1/3 times what=-1?
-3

y=mx+b
m=slope
y=-3x+b
find b

(-3,2)
(x,y)
x=-3
y=2

2=-3(-3)+b
2=9+b
mnus 9
-7=b

equaton is
y=-3x-7 or
3x+y=-7

5would be the answer- explanation