(100 POINTS PLUS BRAINIEST IF CORRECT I NEED HELP FAST) The table below shows all of the possible outcomes for rolling two six-sided number cubes. A table with 36 possible outcomes. There are 9 desired outcomes. What is the probability of rolling an even number first and an odd number second?
StartFraction 1 over 9 EndFraction
StartFraction 1 over 6 EndFraction
One-fourth
One-half

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The of getting an even number in first and an odd number second is 1/4 or 0.25

Step-by-step explanation:

Given,

Total number of outcomes = 36

We have to find the probability of rolling an even number first and an odd number second.

Solution,

Firstly we will find out the possible outcomes;

(2,1)(2,3)(2,5)(4,1)(4,3)(4,5)(6,1)(6,3)(6,5)

So the total number of outcomes = 9

Now according to the formula of probability, which is;

P(E)= total number of possible outcomes/total number of outcomes

Now on putting the values, we get;

P(of getting an even number in first and an odd number second)= 9/36 = 1/4 =0.25

Hence The of getting an even number in first and an odd number second is

1/4 or 0.25.

Hope this help

i would be 2,000 just get the square root of 50 which is 2500 and the divid 4/5 and last thing multiply the answer you get for that by the square root of 50

step-by-step explanation: