Section A has 80 marks Section B has 120 marks. Riya scores
55% in Section A 70% in Section B.
To pass, Riya needs to score 65% of the total marks.
Does she pass? You must show your working.

Riya does not pass

Step-by-step explanation:

From the question:

Section A has 80 marks

Section B has 120 marks.

The total marks from both sections = 200 marks

To pass, Riya needs to score 65% of the total marks.

Hence: 65% of 200 marks

= 65/100 × 200

= 130 marks.

To pass Riya must score 130 marks.

Riya scores:

For section A

55% in Section A

Her marks in section A = 55% × 80

= 55/100 × 80

= 44 marks

For section B

70% in Section B.

Her marks in section A = 70% × 120

= 70/100 × 120

= 84 marks

Therefore , the total marks Riya scored in both sections =

44 marks + 84 marks

= 128 marks

Riya scored a total of 128 marks. SHE DOES NOT PASS. Because the pass mark is a total of 130 marks from Section A and Section B

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this