What is the solution to the following equation 2x^2-3x 2=0?

Here you have a quadratic equation with one unknown variable (x). Since the equation is set equal to 0, we solve for it by factoring the left hand side of the equation and then apply the zero product property to solve for the unknown variable (x). 

Factoring:          2x2 + 3x - 2 = 0

                        (2x - 1)(x + 2) = 0

Zero product property:          (2x - 1)(x + 2) = 0

                                   2x - 1 = 0              AND            x + 2 = 0

          2x - 1 = 0                              AND             x + 2 = 0

             + 1    + 1                                                  - 2     - 2

              2x = 1                                                        x = -2

     (2x) / 2 = (1) / 2

              x = 1/2

Thus, the solution to this equation is:       x = 1/2     and     x = -2

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

answer: what do you mean