Given a quadrilateral DEFG. If angle ED is supplementary to then DEFG is a parallelogram . A. angle EFG and angle DEF B. angle DGF and angle EFC C. angle DEF and angle DGF

The correct option is A.

Step-by-step explanation:

It is given that  DEFG is a parallelogram.

Draw the diagonals DF and EG. Place point H where DF and EG intersect.

In triangle HGD and HEF

,

∠HGD ≅ ∠HEF                            (Alternate Interior angle)

∠HDG ≅ ∠HFE                      (Alternate Interior angle)

By the definition of a parallelogram, the opposite sides of a parallelogram are congruent.

DG ≅ EF                                      (Opposite sides of parallelogram)

According to ASA postulate :

two triangles are congruent if any two angles and their included side are equal in both triangles.

So, by using ASA criterion for congruence we get,

ΔDGH ≅ ΔFEH

Since corresponding sides of congruent triangles are congruent, therefore

GH ≅ EH                      (CPCTC)

DH ≅ FH                     (CPCTC)

step-by-step explanation: you take each of the numbers and divide by the amount then you take the range

the infinity sign

step-by-step explanation: