For questions 9 and 11, solve for the remaining angles.

‹A = 141°

‹B = 28°

‹C = 11°

*These angles are rounded to the nearest whole*

Step-by-step explanation:

Because you are only given sides you can find an individual angle measures with the inverse law of cosines.

Remember the side opposite of the angle corresponds to that angle.

a² = b² + c² - 2bc cos(A) →

A = cos⁻¹ (a² - b² - c² / -2bc)

b² = a² + c² - 2ac cos(B) →

B = cos⁻¹ (b² - a² - c² / -2ac)

c² = a² + b² - 2ab cos(C) →

C = cos⁻¹ (c² - a² - b² / -2ab)