Damarcus and Xavier went to the arcade to play their two favorite games. Damarcus played 4 rounds of game 1 and 6 rounds of game 2 for $18.00. Xavier played 5 rounds of each game for $20. What is the cost of game 1? A. $1.00 B. $2.00 C. $3.00 D. $4.00

The correct option is (c).

Step-by-step explanation:

Let x and y denote the cost of game 1 and game 2 respectively.

ATQ,

4x+6y = 18  (1)

5x + 5y = 20 (2)

Multiply equation (1) by 5 and equation (2) by 4.

20x+30y = 90 (3)

20x + 20y = 80 (4)

Subtracting equation (3) and (4)

20x+30y - (20x + 20y) = 90-80

20x-20x+30y-20y = 10

10y = 10

y = 1

Put the value of y in equation (1).

4x+6(1) = 18

4x = 18-6

4x = 12

x = 3

Hence, the cost of game 1 is $3.00

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.