How many L of A 90% saline solution must be mixed with 4 L of a 50% saline solution to make a 74% solution ?

6 L

Step-by-step explanation:

Given two solutions:

1st solution is 90% saline solution. Let the volume of this solution be litres.

2nd solution is 50% saline solution. Volume of this solution = 4 L

Resultant solution is 74% saline.

To find:

The volume of 1st solution = ?

Solution:

Total volume of the 74% saline mixture = (4+) Litres

We can write equation here, as per the percentage of saline in the mixtures.

90% of L + 50% of 4 L = 74% of (+4)

Therefore, the volume must be 6 L.

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify

english, cause i can’t you