A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second. equation: y=−16x^2+177x+98

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

It hits the ground when , so we have to find x for which , which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

.

This polynomial has roots such that , given by the following formulas:

In this question:

So

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

536

step-by-step explanation:

the answer will be b x² +x-1

step-by-step explanation: