TEACHER QUESTION For the past ten years, Michelle has been tracking the average annual rainfall in Boynton Beach, Florida by recording her data in the given table. She has concluded that the relationship can be modeled by a linear function.

Year 2004 2005 2006 2007 2008 2009 2010 2011 2012 2013
Average Rainfall(in inches) 62.33 61.8 61.27 60.74 60.21 59.68 59.15 58.62 58.09 57.56
Based on the data provided in Michelle's table, use complete sentences to explain how the average rate of change in Boynton Beach's rainfall for the years 2004-2013 can be found. Use the data provided in the table to calculate the average rate of change in precipitation.
Use complete sentences to explain what the average rate of change means in terms of the average rainfall.
IF PUT DOWN JUST BECAUSE YOU WANT POINTS WARNING POINTS INFLATED

Step-by-step explanation:

Year 2004: 62.33

Year 2013: 57.67

2013-2004 = 9

57.67-62.33 =-4.66

-4.66/9 = -0.517777778 which is the average rate of change

Here the the avg. rate of change means that on average, the change in rainfall every year is -0.517777... inches

the answer is 0.3175 hope that you ^w^

also you might actually want to put this picture up if you want people to solve it luckily i remember this question

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.