What is the perimeter of a quadrilateral with vertices at
(3,- 6),
(8,-6), (3, -4), and (8. – 4)? Enter the answer in the box.

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.

multiplication is multiplication.   it might feel harder depending on what level of math you are in, but generally it will be the same old stuff, while implementing some new concepts and methods of solving work.

i believe it’s 165 because if u add 137 and 58 u get 195 and then subtract that from 360 and there’s ur answer

hd extra 3-7 x d en is the answer