Shaneya purchased a membership to play basketball at her local gym. The membership costs $450 for the year, plus she pays $10 to rent equipment each time she goes. If Shaneya doesn't want to spend any more than $1,000 on basketball for the year, what is the maximum amount of times can she go to the gym to play?

55

Step-by-step explanation:

So start with the total 1,000

then take the 1,000 and minus it by the 450 year so then you can see how much money you have left for the times that she can go to the gym to play.

1,000 - 450 = 550

Now you 550 dollars because basic math. Then you divide the number you got which the number you got was 550 so 550÷10 you divide it by 10 because the rent is 10 each time.

550 ÷ 10 = 55

Now you get 55 so that means she can got to the gym 55 times before she goes over 1,000 dollars!

Hoped this helped. Don't forget a middle school person did this so I bet you could have too!

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240