Find the zeros of the polynomial function and state the multiplicity of each. f(x) = 5(x + 7)2(x - 7)3
-7, multiplicity 2; 7, multiplicity 3
4, multiplicity 1; -7, multiplicity 3; 7, multiplicity 3
-7, multiplicity 3; 7, multiplicity 2
4, multiplicity 1; 7, multiplicity 1; -7, multiplicity 1

f(x) = 5(x + 7)2(x - 7)³

-7, multiplicity 2; 7, multiplicity 3

Step-by-step explanation:

Explanation:-

Given function  f(x) = 5(x + 7)2(x - 7)³ =0

⇒   (x + 7)2(x - 7)³ =0

⇒     x = -7  and x =7 multiplicity '3'

-7, multiplicity 2; 7, multiplicity 3

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15