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Mathematics, 12.01.2021 09:00 jaymiahyman123

Determine whether each relation is a function or not a function. Yes, it is a function. No, not a function.
{
(
0
,
3
)
(
2
,
βˆ’
4
)
(
4
,
βˆ’
2
)
(
3
,
βˆ’
4
)
}
Yes, it is a function. – start set open paren 0 comma 3 close paren times open paren 2 comma negative 4 close paren times open paren 4 comma negative 2 close paren times open paren 3 comma negative 4 close paren end set
No, not a function. – start set open paren 0 comma 3 close paren times open paren 2 comma negative 4 close paren times open paren 4 comma negative 2 close paren times open paren 3 comma negative 4 close paren end set
{
(
2
,
βˆ’
3
)
(
βˆ’
2
,
βˆ’
4
)
(
4
,
βˆ’
2
)
(
βˆ’
4
,
βˆ’
4
)
}
Yes, it is a function. – start set open paren 2 comma negative 3 close paren times open paren negative 2 comma negative 4 close paren times open paren 4 comma negative 2 close paren times open paren negative 4 comma negative 4 close paren end set
No, not a function. – start set open paren 2 comma negative 3 close paren times open paren negative 2 comma negative 4 close paren times open paren 4 comma negative 2 close paren times open paren negative 4 comma negative 4 close paren end set
{
(
1
,
3
)
(
2
,
βˆ’
4
)
(
2
,
2
)
(
1
,
βˆ’
4
)
}
Yes, it is a function. – start set open paren 1 comma 3 close paren times open paren 2 comma negative 4 close paren times open paren 2 comma 2 close paren times open paren 1 comma negative 4 close paren end set
No, not a function. – start set open paren 1 comma 3 close paren times open paren 2 comma negative 4 close paren times open paren 2 comma 2 close paren times open paren 1 comma negative 4 close paren end set
{
(
0
,
0
)
(
3
,
5
)
(
5
,
7
)
(
7
,
9
)
}
Yes, it is a function. – start set open paren 0 comma 0 close paren times open paren 3 comma 5 close paren times open paren 5 comma 7 close paren times open paren 7 comma 9 close paren end set
No, not a function. – start set open paren 0 comma 0 close paren times open paren 3 comma 5 close paren times open paren 5 comma 7 close paren times open paren 7 comma 9 close paren end set
{
(
10
,
7
)
(
12
,
βˆ’
8
)
(
βˆ’
4
,
βˆ’
12
)
(
10
,
βˆ’
3
)
}

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Answers: 3

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