The average time spent sleeping (in hours) for a group of medical residents at a hospital can be approximated by a normal distribution. The average is 6.1 hours with a standard deviation of 1 hour. a. What is the shortest time spent sleeping that would place a resident in the top 5% of sleeping times

7.75 hours

Step-by-step explanation:

Given that:

Mean, m = 6.1

Standard deviation, s = 1

Shortest Time spent sleeping in other to be in top 5% of sleeping time.

5% = 0.05

Zscore for P(Z > 0.05) = 1.645 (Z probability calculator)

To obtain the shortest time, x

Zscore = (x - m) / s

1.645 = (x - 6.1) / 1

1.645 = x - 6.1

1.645 + 6.1 = x

7.745 = x

x = 7.75

Sgirtws sleep time = 7.75 hours

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

f(x)=2/3x-8, which give g(x) the greatest value.

step-by-step explanation: