Graph a line with a slope of 3/4 that contains the point (2, -3)

Im assuming this is one of those things that you move the dots around and the line goes with it...?

you would want to put one of the dots on the point (2,-3) because that needs to be on the line, then you put the other dot 3 units up and 4 units over from that which would be at (5,1) because that's the slope specified

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )