Assume that Q, R, and S are the angles of a triangle, with opposite sides q, r, and s respectively. Select all of the following that represent the law of cosines. q2 = r2 + s2 – 2rscos(Q)

q2 = r2 + s2 – 2qscos(R)

r2 = q2 + s2 – 2qscos(Q)

r2 = q2 + s2 – 2qscos(R)

s2 = q2 + r2 – 2qrcos(S)

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5

step by step explanation: when u removing the parentheses and combined them that would be : x+3y-x-y=2y