Use the information to answer the question A diver is swimming at an elevation of -8 feet when she starts to descend at a rate of 2 feet per second for 7 seconds.
What is the diver's elevation after she descends for 7 seconds? Enter the answer in the box.
feet

-22 ft.

Step-by-step explanation:

So we know that the diver descends (goes deeper) at a rate of 2 feet per second.

We also know that he/she is already at an elevation of -8 feet.

The first we need to do to solve this question is to find out the number of feet the diver descends in 7 seconds:

We do this by multiplying the amount of time by the number of feet (7 x 2)

as we all know 7 x 2 = 14 feet

So the diver dove deeper by 14 feet.

Now we have to add 14 and 8 to find the divers new elevation:

14 + 8 = -22 ft.

The divers' elevation after descending for 7 seconds is -22 ft.

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step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm