Write an equation of a line that passes through the point (4,3) and is perpendicular to the graph of the equation y=−13x+4.

An equation of a line that passes through the point (4,3) and is perpendicular to the graph of the equation will be:

Step-by-step explanation:

We know that the slope-intercept form of the line equation is

where

Given the line

y = -13x+4

comparing with the slope-intercept form of the line equation

The slope of the line = m = -13

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

slope = m = -13

Thus, the slope of the the new perpendicular line = – 1/m = -1/-13 = 1/13

Using the point-slope form of the line equation

where

substituting the values of the slope m = 1/13 and the point (4, 3)

Add 3 to both sides

Therefore, an equation of a line that passes through the point (4,3) and is perpendicular to the graph of the equation will be:

351°f

step-by-step explanation:

step-by-step explanation:

the triangles are similar. therefore the corresponding sides are in proportion:

              cross multiply

            divide both sides by 32