Develop an estimate for each of the following situations.(at) The cost of a 500-mile automobile trip, if gaso-line is $4 per gallon, vehicle wear and tear is$0.65 per mile, and our vehicle gets 25 miles pergallon.(b) The total number of hours in the average humanlife, if the average life is 75 years.(c) The number of days it takes to travel around the equator using a hot air balloon, if the balloon

The answer is below

Step-by-step explanation:

develop an estimate for each of the following situations.

(a) The cost of a 500- mile automobile trip, if gasoline is $4.00 per gallon, vehicle wear and tear is $0.65 per mile, and our vehicle gets 25 miles per gallon.

(b) The total number of hours in the average human life, if the average life is 75 years.

(c) The number of days it takes to travel around the equator using a hot air balloon, if the balloon averages 100 miles per day, the diameter of the earth is ~4,000 miles.

Solution:

a) The total trip = 500 mile

Cost of wear and tear = $0.65 per mile = $0.65 * 500 mile = $325

25 miles takes 1 gallon of gasoline at a cost of $4 per gallon

Cost of gasoline = $4 per gallon * 500 miles / 25 miles per gallon = $80

cost of a 500-mile automobile trip = Cost of wear and tear + Cost of gasoline = $325 + $80 = $405

b) Average life of human = 75 years.

1 year = 365 days, 1 day = 24 hours

Average life of human in hours = 75 years * 365 days * 24 hours =657000 hours

c) Diameter of earth = 4000 miles

Distance of equator = diameter of earth = 4000 miles

100 mile per day

number of days for the balloon to travel round the earth = 4000 miles / (100 mile per day) = 40 days