HURRY PLEASE!
(g+2)^5...
Answers: 1
Mathematics, 21.06.2019 12:30
An arrow is shot vertically upward at a rate of 180ft/s. use the projectile formula h=−16t2+v0t to determine at what time(s), in seconds, the arrow is at a height of 420ft. round your answer(s) to the nearest tenth of a second.
Answers: 1
Mathematics, 21.06.2019 15:00
1. are the triangles similar and if so why? what is the value of x? show your work.
Answers: 1
Mathematics, 21.06.2019 15:30
The diameter of a circular chip is doubled to use in a new board game. the area of the new chip will be
Answers: 2
Mathematics, 21.06.2019 21:30
In δabc shown below, ∠bac is congruent to ∠bca: triangle abc, where angles a and c are congruent given: base ∠bac and ∠acb are congruent. prove: δabc is an isosceles triangle. when completed (fill in the blanks), the following paragraph proves that line segment ab is congruent to line segment bc making δabc an isosceles triangle. (4 points) construct a perpendicular bisector from point b to line segment ac . label the point of intersection between this perpendicular bisector and line segment ac as point d: m∠bda and m∠bdc is 90° by the definition of a perpendicular bisector. ∠bda is congruent to ∠bdc by the definition of congruent angles. line segment ad is congruent to line segment dc by by the definition of a perpendicular bisector. δbad is congruent to δbcd by the line segment ab is congruent to line segment bc because consequently, δabc is isosceles by definition of an isosceles triangle. 1. corresponding parts of congruent triangles are congruent (cpctc) 2. the definition of a perpendicular bisector 1. the definition of a perpendicular bisector 2. the definition of congruent angles 1. the definition of congruent angles 2. the definition of a perpendicular bisector 1. angle-side-angle (asa) postulate 2. corresponding parts of congruent triangles are congruent (cpctc)
Answers: 1
Social Studies, 20.11.2020 17:00
History, 20.11.2020 17:00
Mathematics, 20.11.2020 17:00
Mathematics, 20.11.2020 17:00
Physics, 20.11.2020 17:00
Mathematics, 20.11.2020 17:00
Mathematics, 20.11.2020 17:00