A JIT system uses kanban cards to authorize movement of incoming parts. In one portion of the system, a work center uses an average of 105 parts per hour while running. The manager has assigned an inefficiency factor of .35 to the center. Standard containers are designed to hold 3 dozen parts each. The cycle time for parts containers is about 90 minutes. How many containers are needed

6 Containers are needed

Step-by-step explanation:

The ideal number of Kanban cards can be calculated using the following formula;

N = (DT × ( 1 + X)) / C

where N is total number of container,

D is panned usage rate of using work Centre

T is Average waiting time for replenishment of parts plus average production for a  container of parts,

X is policy variable set by management that reflects possible inefficiency in the system ,

C is capacity of standard container.

Now, given that;

D = 105 parts

T = 90min = 90/60 = 1.5 hrs

X = 0.35

C = 3 × 12parts = 36 parts

so; we substitute

N = (105×1.5 × ( 1 + 0.35)) / 36

N = 212.626 / 36

N = 5.9063 ≈ 6

Therefore 6 Containers are needed

3x3 = 9 and 2x2 = 4

step-by-step explanation:

36 is the final answer! : )