7. In the figure, P, Q and R points on level ground in a park. R is 600 m from Q and on a bearing of 305° from Q. Q is 950 m from P and on a bearing of 078° from P Im having trouble with finding the distance.

The answer is below

Step-by-step explanation:

From the image:

∠P + ∠Q = 180° (consecutive angles are supplementary)

78 + ∠Q = 180

∠Q = 180 - 78

∠Q = 102°

∠RQN = 360° - 305° =(sum of angle in a point)

∠RQN = 55°

∠RQN + ∠RQP = 102°

∠RQP = 102 - 55 = 47°

a) Let PR = x

Using cosine rule:

Therefore PR = 696 m

b) Let ∠RPQ be A°

Using sine rule:

∠RPQ = 39°

Hence the bearing of R from P = ∠NPR = 78° - 39° = 39°

its d. the first coordintaes are 10,32

step-by-step explanation: