The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixed at 2.52.52, point, 5 kilometers. At a certain instant, the radius is 404040 kilometers. What is the rate of change of the volume of the cylinder at that instant (in cubic kilometers per second)

7536

Step-by-step explanation:

Given that:

Rate of decreasing of radius = 12 km/sec

Height of cylinder is fixed at = 2.5 km

Radius of cylinder = 40 km

To find:

The rate of change of Volume of the cylinder?

Solution:

First of all, let us have a look at the formula for volume of a cylinder.

Where is the radius and

is the height of cylinder.

As per question statement:

= 40 km (variable)

= 2.5 (constant)

As are constant:

a) t'(-3, 6) and v'(0, 3)  

step-by-step explanation:

bn,mn,n.vn.

step-by-step explanation: