The perimeter of a rectangle a picture frame is 66 inches. the length is 3 inches greater than the width the system of linear equations used to represent the situation shown below. 2X + 2Y = 66 and X +3 =Y

solve the system name dimension represented by each variable

Given:

To find: The dimensions.

Formula to find the perimeter of a rectangle = 2 × (Length + Width)

We know that 2X + 2Y = 66. Simplifying it, we get:

2(X + Y) = 66

X + Y = 66/2

X + Y = 33

Now that we know the value of X + Y, and assuming X and Y to be the dimensions, let's substitute it into the formula to find the perimeter and verify it.

Perimeter = 2 × (X + Y)

66 = 2 × 33

It's verified.

Now, we also have the expression representing the length, which is X + 3 = Y.

X + Y = 33

X + 3 = Y

Let's add both expressions.

X + Y + X + 3 = 33 + Y

2X + Y + 3 = 33 + Y

2X = 33 - 3 + Y - Y

2X = 30

X = 30/2

X = 15

Hence, the width [X] is 15.

Substituting this value into the expression representing the length,

15 + 3 = Y

18 = Y

Hence, the length and breadth of the rectangular picture frame is 18 and 15 units respectively.

Hope it helps. :)

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?