At the beginning of the year Monica puts a set amount of money into her health benefit account. Every month she withdraws $15 from this account for her contact lenses. After 3 months she has $255 left in her account. Write an equation in slope-intercept form to represent the relationship between the time that has passed and the amount of money left in Monica's account. Let x represent the time in months and y represent the amount of money remaining in the account.

An equation in the slope-intercept form will be:

Step-by-step explanation:

We know The slope-intercept form of the line equation

where

Let x represent the time in months

Let y represent the amount of money remaining in the account.

Given that every month Monica withdraws $15 from this account for her contact lenses

Thus, the rate of change or slope = m = 15

Given that after 3 months she has $255 left in her account.

So, we take the point (3, 255)

substituting m = 15, x = 3 and y = 255 in the slope-intercept form to determine the y-intercept

y = mx+b

255 = 15(3) + b

switch sides

15(3) + b = 255

45 + b = 255

b = 255 - 45

b = 210

Now, substituting m = 15 and b = 210 in the slope-intercept form of the line equation

y = mx+b

y = 15x+210

Therefore, an equation in the slope-intercept form will be:

answer: there are 453.592 grams in a pound.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116