PLEASE HELP TIMED Suppose the following set of random numbers is being used to simulate the event of a basketball player making five free throws in a row. How should the numbers be rearranged?

860583 785814 010122 337198 621549 034076 796495 978078 433330 333153

A.
860583 785814 010122 337198 621549 034076 796495 978078 433330 333153

B.
86058 37858 14010 12233 71986 21549 03407 67964 95978 07843 33303 33153

C.
860 583 785 814 010 122 337 198 621 549 034 076 796 495 978 078 433 330 333 153

D.
8605 8378 5814 0101 2233 7198 6215 4903 4076 7964 9597 8078 4333 3033 3153

answer: the area of the parallelogram below is 42 square meters.

- officialprodixy ☕

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: i'm great at algebra

~coco

step-by-step explanation:

need more information

step-by-step explanation: