A=|3x-6| + 2 , xeR
prove that:
A=3x-4 for every x≥2

We know that the function IxI is such that:

IxI = x if x ≥ 0

IxI = -x if x < 0.

In this case, we have:

A = I3x - 6I + 2

If we do the same as above, we can write:

A = (3x - 6) + 2       if (3x - 6) ≥ 0

Let's look at the condition in the right, let's isolate the variable:

(3x - 6) ≥ 0

3x ≥ 6

x ≥ 6/3 = 2

Then the condition:

(3x - 6) ≥ 0

is equivalent to:

x ≥  2

Then we can write:

A = (3x - 6) + 2      if  x ≥ 2

If we simplify it further, we get:

A = 3x - 6 + 2        if  x ≥ 2

A = 3x - 4               if  x ≥ 2

This is what we wanted to prove.    

figure c

step-by-step explanation:

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