In the given diagram ⃤ ABC and ⃤ CDE are equilateral triangles. If ∠EBD = 62° then find the measure of 1/2 of ∠AEB.

Given

△ABC and △CDE are equilateral.

AE

= 25

To find perimeters of the two triangles,

Let us consider the lengths of

AC

and

CE

to be

′

x

′

and

′

y respectively.

As △ABC is equilateral,

AC

=

AB

=

BC

= x

As △CDE is equilateral,

CE

=

CD

=

DE

= y

From the figure,

AE

=

AC

+

CE

25 = x + y

x + y = 25

Perimeter of the triangle is the sum of all sides of the triangle.

For △ABC,

Perimeter of △ABC =

AC

+

AB

+

BC

= x + x + x

= 3x

For △CDE,

Perimeter of △CDE =

CE

+

CD

+

DE

= y + y + y

= 3y

Now,

Perimeter of two triangles = Perimeter of △ABC + Perimeter of △CDE

= 3x + 3y

= 3 × (x + y)

= 3 × 25 (from above)

= 75

Therefore, Perimeter of the two triangles is'75′units.

Step-by-step explanation:

Hope it is helpful...

g(x) is the negative form of f(x)? because whenever its the negative form it reflects its self over the x axis. idk if this is right though.

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it