Find the values of y for which the distance between the point p2,-3 and q 10, y is 10 units

y = - 9, y = 3

Step-by-step explanation:

Calculate distance d using the distance formula

d =

with (x₁, y₁ ) = (2, - 3) and (x₂, y₂ ) = (10, y)

d =

   =

Given distance between points is 10, then

= 10 ( square both sides )

64 + (y + 3)² = 100 ( subtract 64 from both sides )

(y + 3)² = 36 ( take the square root of both sides )

y + 3 = ± = ± 6 ( subtract 3 from both sides )

y = - 3 ± 6 , thus

y = - 3 - 6 = - 9

y = - 3 + 6 = 3

where's the diagrams?