A) If a and B are the roots of the equation 3.x2 - 6x + 5 = 0, find the equation whose roots are a + B and
2÷a+B

Step-by-step explanation:

α and β are roots of 3x² - 6x + 5 = 0.

By Vieta's Formula,

we have αβ = 5/3 and α + β = 2.

To find the equation with roots α + β and 2/(α + β),

we find the Sum and Product of these roots.

=> Sum = (α + β) + 2/(α + β) = (2) + 2/(2) = 3.

=> Product = (α + β) * 2/(α + β) = 2.

Hence we have Ax² + Bx + C,

where -B/A = 3 and C/A = 2.

Simplest form is A = 1, B = -3, and C = 2.

Hence the equation with roots

α + β and 2/(α + β) is x² - 3x + 2.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.