A rectangular soccer field may have a width between 50 and 100 yards and a length between 100 and 130 yards. One particular soccer field has a perimeter of 320 yards. Its
length measures 40 yards more than its width. What are the dimensions of this field?

The length is___yards.

The width isyards.

9514 1404 393

Step-by-step explanation:

Let w represent the width of the field. Then the length is (w+40), and the perimeter is ...

  P = 2(L +W)

  320 = 2((w+40) +w) . . . . fill in values

  160 = 2W +40 . . . . . . . . . divide by 2, collect terms

  80 = w +20 . . . . . . . . . . .  divide by 2

  60 = w . . . . . . . . subtract 20

  w+40 = 100

The length is 100 yards; the width is 60 yards.

the answer is stop cheating on things stoopid

step-by-step explanation:

im eatin up the 44

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92