If (3a + 3b + 1) (3a + 3b - 1) = 80, then what is a + b?

a + b = 3 -       maybe

Step-by-step explanation:

( 3a + 3b + 1 )( 3a + 3b - 1 ) = 80

Expand

9a² + 9ab - 3a + 9ab + 9b² - 3b + 3a + 3b - 1 = 80

Simplify

9a² + 9b² + 18ab - 1 = 80

move the 1 over

9a² + 9b² + 18ab = 81

divide by 9

a² + b² + 2ab = 9

not really sure after this part

move the 2ab over

a² + b² = 9 - 2ab

square root both sides

a + b =

simplify

a + b = 3 -

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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