Two number cubes, one red and one blue, are rolled. What is the probability that the outcome of the red number cube is even and the outcome of the blue number cube is a 5

The probability is 0.083

Step-by-step explanation:

First, let's find the individual probabilities:

The probability that the outcome of the red number cube is even:

This will be equal to the quotient between the number of outcomes that are even (3) and the total number of outcomes for this dice (6)

Then the probability is:

p = 3/6 = 1/2.

The probability that the outcome of the blue number cube is a 5.

Similar to the above case, here the probability will be the quotient between the number of outcomes that are 5 (only one) and the total number of outcomes.

q = 1/6

And the joint probability will be equal to the product of the individual probabilities, then he probability that the outcome of the red number cube is even and the outcome of the blue number cube is a 5 is equal to:

P = p*q = (1/2)*(1/6) = 1/12 = 0.083

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

step- i d k and i d c : )

you: : 0

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