You have the same bowl, with 5 orange, 6 blue, 3 green, 4 red and 7 yellow candies. You take out an orange candy from the bowl. What is the new probability that you will draw another orange candy?
A 1/5
B 1/6
C 1/8
D 5/24

A) 1/5

Step-by-step explanation:

There are 25 candies total, and you want to choose the 5 orange candies there.

That's 5/25.

Simplifying, we divide both sides by 5.

Thus, we get:

1/5.

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb