1)10 = z+ 6 2) 8y = 48
3) q-12 = 1
6)11 = m-4
7)t-19=2
8)1+S = 3
9)24 = 4c
Please explain how these are solved please respond quickly

1. Z=4 10-6
2 y= 6 48/8
3. Q= 13 12+1
6 m=15 11+4
7. 21 19+2
8. S=2 3-1
9. C=6 24/4

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*