Which statement correctly names the congruent triangles and justifies the reason for congruence? triangles DEF and ACB on a coordinate plane at D 1 comma 5, E 2 comma 7, F 4 comma 5, A 4 comma 4, B 4 comma 1, and C 2 comma 3, angle E measures 63 degrees, angle F measure 45 degrees, angle C measures 63 degrees, and angle B measures 45 degrees

ΔBAC ≅ ΔFDE by HL
ΔBAC ≅ ΔDEF by HL
ΔBAC ≅ ΔFDE by AAS
ΔBAC ≅ ΔDEF by AAS

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

6/20

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

2+2 obliviously is 4.