If 2^x3^y=18 and 2^x×3^y=36 then find the value of x and y

x = 1

y = 2

Step-by-step explanation:

x=1 and y=2.

step 1 ,

2^2x*3^y=36

3^y= 36/2^2x ———- equal 1

step 2,

put the value of 3^y in 2^x*3^y = 18 (equal 1)

WHEN BASES ARE SAME POWERS ARE SUBTRACTED IN CASE OF DIVISION.

Therefore, 2^x-2^2x= 1/2

2^-x= 1/2

(1/2)^x = 1/2

COMPARING THE POWERS BECAUSE THE BASE IS SAME.

x=1.

Now, putting the value of x=1 in 2^x*3^y = 18

y=2.

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.

what is the original number? you forgot to add it.