what is an equation of the line that passes through the point (-6,-1) and is perpendicular to the line 6x-y=7? (has to be in y=mx+b form)

y = x - 2

Step-by-step explanation:

Slopes of perpendicular lines are opposite reciprocals.

If AB ⊥ CD , then = - 1

y - = m(x - )

~~~~~~~~~~~

6x - y = 7 ⇔ y = 6x - 7

Slope of given line is 6

Slope of a perpendicular line is

( - 6, - 1 )

y + 1 = (x + 6)

y = x - 2

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step-by-step explanation:

the radius is 2 times the diameter.

step-by-step explanation: