Use Phythagoras Theorem!! the length pf a rectangle is 50 cm and its diagonal is 51 cm. work out the area of the rectangle, to the nearest square centimetre.

a² + b² = c²

50² + 51² = c²

2500 + 2601 = c²

5101 = c²

√5101 ≈ 71.42 cm.

Area of the rectangle = 102.5 cm²  Round to 103 cm²

Step-by-step explanation:

The diagonal is the hypotenuse, c So subtract the square on the base (length) to find the altitude (height).

a² + b² = c²

a² + 50² = 51²

a² = 51² - 50²

a² = 2601 -2500

a² = 101  take the square root of both sides

a = √101

a = 10.04987562  Round to 10.05

Area = LW

Area = 50 × 10.05

Area = 102.5 cm²  Round to 103 cm²

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1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x