The following data are the distances between a sample of 20 retail stores and a large distribution center. The distances are in miles. 29; 31; 34; 40; 58; 67; 68; 69; 76; 80; 82; 95; 96; 96; 99; 106; 112; 127; 145; 150 Find the value that is one standard deviation below the mean. (Round your answer to one decimal place.)

47.8

Step-by-step explanation:

Given the data:

29; 31; 34; 40; 58; 67; 68; 69; 76; 80; 82; 95; 96; 96; 99; 106; 112; 127; 145; 150

Mean (m) = ΣX / n

n = sample size

ΣX = 1660

Mean = 1660 / 20

Mean (m) = 83

Standard deviation(s) : √(Σ(X - m)² / n-1)

Σ(X - m)² = (29-83)^2 + (31-83)^2 + (34-83)^2 + (40-83)^2 + (58-83)^2 + (67-83)^2 + (68-83)^2 + (69-83)^2 + (76-83)^2 + (80-83)^2 + (82-83)^2 + (95-83)^2 + (96-83)^2 + (96-83)^2 + (99-83)^2 + (106-83)^2 + (112-83)^2 + (127-83)^2 + (145-83)^2 + (150-83)^2

√(23608 / (20-1))

√23608/ 19

√1242.5263

= 35.249486

= 35.25

Mean -1(s)

83 -35.25

47.75

=47.8

idk

step-by-step explanation: