I need help with this Geometry question

A) 6 in^2

First, you need to find the length of the base.

a = 3, b = ?, c= 5

Using Pythagorean Theorem*: a^2 + b^2 = c^2

b^2 = c^2 - a^2

b^2 = 5^2 - 3^2

b^2 = 25 - 9

b^2 = 16 (square root both sides)

b = 4

Now, you have to find the area using the area of a triangle formula: A = (bh)/2

A = (bh)/2

A = (4·3)/2

A = 12/2

A = 6 in^2

Pythagorean Theorem is used for this question since it's a right triangle.

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

i can answer this question sweetie!

step-by-step explanation: