How do you factor 12j^2k - 36j^6k^6 12j^2?

12j^2k - 36j^6k^6 + 12j^2 = 12j^2(k - 3j^4k^6 + 1)

0=6x+2y+10 is equivalent to the simplified form: y= -3x - 5• parallel lines always have the same slope, different y intercept knowing this, we can say the slope, or m of the line parallel to y= -3x - 5 is -3.m= -3 hope this could !