Nancy buys 2 large pizzas for her brother's birthday party. The girls at the party eat 78 of a large pizza. The boys at the party eat 58 of a large pizza. Nancy says about 112 pizzas were eaten at the party. Is Nancy correct? Nancy is wrong because 78 is close to the benchmark 12 and 58 is close to the benchmark 12 and 12 + 12 = 1.

Nancy is wrong because 78 is close to the benchmark 1 and 58 is close to the benchmark 0 and 1 + 0 = 1.

Nancy is correct because 78 is close to benchmark 1 and 58 is close to benchmark 12 and 1 + 12= 112. .

Nancy is wrong because 78 is close to benchmark 1 and 58 is close to benchmark 1 and 1 + 1 = 2.

Successful implementation of a new system is based on three independent modules. module 1 works properly with probability 0.96. for modules 2 and 3, these probabilities equal 0.95 and 0.90. compute the probability that at least one of these three modules fails to work properly.

Which of the following transformations will always produce a congruent figure?

Exercise: counting committees 0.0/2.0 puntos (calificable) we start with a pool of n people. a chaired committee consists of k≥1 members, out of whom one member is designated as the chairperson. the expression k(nk) can be interpreted as the number of possible chaired committees with k members. this is because we have (nk) choices for the k members, and once the members are chosen, there are then k choices for the chairperson. thus, c=∑k=1nk(nk) is the total number of possible chaired committees of any size. find the value of c (as a function of n ) by thinking about a different way of forming a chaired committee: first choose the chairperson, then choose the other members of the committee. the answer is of the form c=(α+nβ)2γn+δ. what are the values of α , β , γ , and δ ?