Mathematics, 07.01.2021 17:10 luvme68297
Ax4+bx3+cx2+dx+e=0 :
[math]x=-\frac{b}{4a}\pm\left(\frac {1}{2}\sqrt{\frac{3b^2-8ac}{12a^2}+ \frac{1}{3a}\left(\sqrt[3]{\frac{2c ^3-9bcd+27b^2e+27ad^2-72ace+\sqrt{\ left(2c^3-9bcd+27b^2e+27ad^2-72ace\ right)^2-4\left(c^2-3bd+12ae\right) ^3}}{2}}+\frac{c^2-3bd+12ae}{\sqrt[ 3]{\frac{2c^3-9bcd+27b^2e+27ad^2-72 ace+\sqrt{\left(2c^3-9bcd+27b^2e+27 ad^2-72ace\right)^2-4\left(c^2-3bd+ 12ae\right)^3}}{2}}}\right)}\right) \pm\frac{1}{2}\sqrt{-4\left(\frac{1 }{2}\sqrt{\frac{3b^2-8ac}{12a^2}+\f rac{1}{3a}\left(\sqrt[3]{\frac{2c^3 -9bcd+27b^2e+27ad^2-7[/math]
only for a luh cutie that i know of ;)
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Ax4+bx3+cx2+dx+e=0 :
[math]x=-\frac{b}{4a}\pm\left(\frac {1}{2}\sqrt{\frac{3b^2-8ac}{12a^2}+ \frac...
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