In quadrilateral ABCD m < A= 90° m 2 C = 50° and m < B = m D.
Find the degree measure of < B.

m∠B = 170°

Step-by-step explanation:

Sum of all angles in quadrilateral is 360°:

m∠A + m∠B + m∠C + m∠D = 360°

m∠B = 360° - m∠A - m∠C - m∠D

m∠A = 90°

m∠B = m∠D= 50°

m∠B =  360° - 90° - 50° - 50° = 170°

answer: can you me with homework?

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