Unit 9-Transformations Homework 2 Reflections
please help me with this question if you cant see the other one i will give you the
graph and label each figure and its image under a reflection in the given line. Give the coordinates of the image
numbers
1. square BCDE with verticles B (-6,7) C (-2,6) D (-3,2) E (-7,3)- y axis
2. triangle FGH with verticles F (1,8) G (5,7) and H (2,3)-y=x
3.trapezoid JKLM with verticles J (-4,3) K (-2,7) L (2,7) M (3,3) y=1
4.rhombus WXYZ with verticles W (1,5) X (6,3) Y (1,1) Z (-4,3)
5.triangle PQR with verticles P (-2,3) Q (2,4) R (1,-1)
6.rectangle MNOP with verticles M (-7,1) N (-4,1) O (-4,-4) P (-7,-4) y=x

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Step-by-step explanation:

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.