Suppose that the following group of values has been entered into the TVM Solver of a graphing calculator: N=300; 1%=7.7; PV=105000; PMT=-
789.65160; FV=0; P/Y=12; C/Y=12; PMT:END. Which of the following uses of
the "bal(" function will give the balance on the loan in question after 11 years?
A. bal(132)
B. bal(168)
C. bal(14)
D. bal(11)

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

step-by-step explanation:

but there’s no any figure there!