A line passes through the points (-8, 7) and (-11,-11). Find the value of a such 1 point that the point (-7,a) lies on the line. a=
Your answer

a=12

Step-by-step explanation:

we need the slope of this line. Find it with the slope formula

m= y2-y1 / x2-x1    with the points given p1=(-8,7)  and p2=(-11,-11)

m=-11-7 / -11-(-8)                                               (x1,y1)               (x2,y2)  

m= -18 /-11+8

m= -18 / - 3

m= 6

next plug in one of the point into the point-slope formula [y-y1=m(x-x1)]

y-7=6(x-(-8))  ( simplify this towards the slope intercept form [y=mx+b]

y-6=6(x+8)

y-6=6x+48

y=6x+54

now we can plug in our point of (-7,a) to find what a is

a=6(-7)+54

a=-42+54

a=12

:)

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step-by-step explanation: