A net for a rectangular prism with dimensions of 1 centimeter, 2 centimeters, and 5 centimeters is given. What is the surface area of this rectangular prism?

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cm²
The figure contains a net of a solid. The net is made up of 6 rectangles. The first rectangle has a length of 5 centimeters and a width of 2 centimeters. Each side of this rectangle shares a side with one other rectangle. The rectangles above it and below it each have a length of 5 centimeters and a width of 1 centimeter. The rectangles to its left and right each have a length of 1 centimeter and a width of 2 centimeters. The sixth rectangle shares its bottom side with the top side of the upper 5 centimeter by 1 centimeter rectangle. The length of the sixth rectangle is 5 centimeters, and its width is 2 centimeters.

34cm^2

Step-by-step explanation:

Step 1: Find the surface area of each side.

Side Dimensons:

(5x2)2

(5x1)2

(2x1)2

Then do the math

5x2=10

10x2=20

20

5x1=5

5x2=10

10

2x1=2

2x2=4

4

Step 2: Add each side together

20+10+4= 34

34cm^2

zero

step-by-step explanation:

f(2)= x-2

plug in the 2 in the "x"

f(2)=2-2

f(2)=0

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.